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這一題算是蠻特別的, 我覺得他不應該放在簡單的行列內, 原則上我認為應該有中間的程度了.
Given two binary strings a
and b
, return their sum as a binary string.
Example 1:
Input: a = "11", b = "1" Output: "100"
Example 2:
Input: a = "1010", b = "1011" Output: "10101"
Constraints:
1 <= a.length, b.length <= 104
a
andb
consist only of'0'
or'1'
characters.- Each string does not contain leading zeros except for the zero itself.
string addBinary(string a, string b) {
int i = a.size() - 1, j = b.size() - 1;
int carry = 0;
string result = "";
while ( i >= 0 || j >= 0 || carry != 0) {
if (i >= 0) {
carry += a[i] == '0' ? 0 : 1;
i--;
}
if (j >= 0) {
carry += b[j] == '0' ? 0 : 1;
j--;
}
result = ((carry % 2) == 0 ? "0" : "1") + result;
carry /= 2;
}
return result;
}
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